\displaystyle\sum_{n=1}^\infty \frac{1}{n^2}=\frac{\pi^2}{6}:
\(\displaystyle\sum_{n=1}^\infty \frac{1}{n^2}=\frac{\pi^2}{6}\)
\underset{n=1}{\overset{\infty}{\Sigma}} \frac{1}{n^2}=\frac{\pi^2}{6}:
\(\underset{n=1}{\overset{\infty}{\Sigma}} \frac{1}{n^2}=\frac{\pi^2}{6}\)
\sqrt{6 \underset{n=1}{\overset{\infty}{\Sigma}} \frac{1}{n^2}}=\pi:
\(\sqrt{6 \underset{n=1}{\overset{\infty}{\Sigma}} \frac{1}{n^2}}=\pi\)
The square root is not well rendered.
Testing
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Testing
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Re: Testing
Seems to be better with chrome than with firefox!
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Re: Testing
Firefox rendering:
Chrome rendering:
Chrome rendering:
DM42 SN00284 running free42 & SN03835 running WP43S, DM15L, HP41CV, HP42S, HP35s, WP34S, HP Prime
Re: Testing
FYI  I'm using FF on Windows and the square root symbol looks fine to me, that is to say, on my FF, the image in your original post just above this one looks the same as you show for "Chrome rendering".
bob p
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DM42: β00071 & 00282, DM41X: β00071 & 00656, DM10L: 071/100
Re: Testing
Same here with FF 81 on Android, I don't see any difference in the rendering between FF and Chrome.
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Re: Testing
It looks great on macOS 10.15.7 with Safari Version 14.0 (15610.1.28.1.9, 15610)
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My Collection: HP55, HP67 (Teenix Mod), HP15C, HP16C, HP41CV, HP41CX, SY41CL (x2), DM41X (Beta), DM42, HP42S, HP48G, HP71B (x2), HP75C, HP150.
Re: Testing
Same here! ... also look great with Firefox 81.0 and Chrome 85.0.4183.121.Dan Simpson wrote: ↑Tue Sep 29, 2020 12:17 amIt looks great on macOS 10.15.7 with Safari Version 14.0 (15610.1.28.1.9, 15610)
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Re: Testing
Like it.
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I may have a problem!
I may have a problem!