0 [1/x] [+/-] returns -∞.
We all know that SQRT(-∞) = i ∞.
The calculator returns 0. + i ∞ which is perfectly equivalent.
Now let's revert this last operation by squaring: (i ∞)^2 = -∞. So far so good.
But (0 + i ∞)^2 = 0 + (-∞) + 2 i 0 ∞ = -∞ + 2 i 0 ∞.
So we must conclude that 0 times ∞ equals 0 which is in contradiction to other people stating 0 times ∞ is undefined or even non-numeric (the calculator returns -∞ + i NaN).
What am I missing?
